解法1:
解:设有
X=0.9999999……①
10X=9.99999999999……②
将②—①,得
10X-X=9.999999……-0.999999…………
9X=9
X=1
故0.999999....循环=1(由①知)
解法2:
1/3=0.333333……,而0.999999……=3×0.333333……=3×(1/3)=1
极限论.....
Why??
解法1:
解:设有
X=0.9999999……①
10X=9.99999999999……②
将②—①,得
10X-X=9.999999……-0.999999…………
9X=9
X=1
故0.999999....循环=1(由①知)
解法2:
1/3=0.333333……,而0.999999……=3×0.333333……=3×(1/3)=1
极限论.....
Why??