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在线等find the equation of tangent to y=1-3x+12x^2-8x^3 which is parallel to the tangent at (1,2)

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解决时间 2021-01-15 06:09
  • 提问者网友:姑娘长的好罪过
  • 2021-01-14 16:31
在线等find the equation of tangent to y=1-3x+12x^2-8x^3 which is parallel to the tangent at (1,2)
最佳答案
  • 二级知识专家网友:逐風
  • 2021-01-14 17:36
1). find the equation of tangent to y=1-3x+12x^2-8x^3 which is parallel to the tangent at (1,2).
2). show that the equation of the tangent to y=2x^2-1 at the point where x=a, is 4ax-y=2a^2+1.
3).y=a根号(1-bx) where a and b are constants, has a tangent with equation 3x+y=5 at the point where x=-1. find a and b.
4). find the equation of the normal to y=根号x from the external point (4,0).
5).consider f(x)=8/^2
a. find the equation of the tangent at the point where x=a.
b.if the tangent in a cuts the x-axis at A and the y=axis at B, find the coordinates of A and B.
求过程。。。在线等

对f(x)求导,即:
f'(x)=x^2-3
y=x的斜率是1,所以
令f'(x)=1
就可以得出x=2,-2
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