初二通分:1除以(x-y)(x-z),1除以(y-z)(y-x)
答案:1 悬赏:50
解决时间 2021-01-11 08:12
- 提问者网友：谁的错
- 2021-01-10 21:29
初二通分:1除以(x-y)(x-z),1除以(y-z)(y-x)
最佳答案
- 二级知识专家网友：渊鱼
- 2021-01-10 23:07
1(X-Y)(X-Z),1(Y-Z)(Y-X),1(Z-X)(Z-Y）分式通分
(y-z)(y-x)=-(y-z)(x-y)
(z-x)(z-y)=(x-z)(y-z)
所以
1/(x-y)(x-z)=(y-z)/[(x-y)(x-z)(y-z)]
1/(y-z)(y-x)=-(x-z)/[(x-y)(x-z)(y-z)]
1/(z-x)(z-y)=(x-y)/[(x-y)(x-z)(y-z)]
(y-z)(y-x)=-(y-z)(x-y)
(z-x)(z-y)=(x-z)(y-z)
所以
1/(x-y)(x-z)=(y-z)/[(x-y)(x-z)(y-z)]
1/(y-z)(y-x)=-(x-z)/[(x-y)(x-z)(y-z)]
1/(z-x)(z-y)=(x-y)/[(x-y)(x-z)(y-z)]
我要举报
如以上回答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！
点此我要举报以上问答信息！
大家都在看
推荐信息